Chapter:

Properties-of-fluid

A plate having an area of `0.6 m^2` is sliding down inclined plane at an angle of `30^0` to horizontal with a velocity of 0.36 m/sec. There is a cushion of fluid 1.8 mm thick between plane and plate. Find viscosity of fluid if weight of plate is 280N.

SOLUTION:

Given,

Area of plate,`A=0.6 m^2`

Velocity of the plate,`u=0.36`m/s

Thickness of the film,`dy=1.8`mm

Weight of the plate,` W=280 N`

Viscosity of the fluid,` mu=?`

A plate having an area of  `0.6 m^2` is  sliding down the inclined plane at an angle of `30^0` to the horizontal with a velocity of 0.36 m/sec. There is a cushion of fluid 1.8 mm thick between the plane and the plate. Find the viscosity of the fluid if the weight of the plate is 280N.

Now,

Shear force on the bottom surface of the plate is given by,

F= component of weight along the plane.

or, `F=W*sin30 =140 N`

Thus, shear stress `tau=F/A=140/0.6 =233.33` N/`m^2`


We have,

`tau=mu*(du)/(dy)`

or, `mu=233.33/0.36 *1.8/1000=1.166....Show More

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This Chapter Properties-of-fluid consists of the following topics