Chapter:
                                                Properties-of-fluid                                            
                                        
                                                             A plate having an area of  `0.6 m^2` is  sliding down  inclined plane at an angle of `30^0` to  horizontal with a velocity of 0.36 m/sec. There is a cushion of fluid 1.8 mm thick between  plane and  plate. Find  viscosity of  fluid if  weight of  plate is 280N.                                                            
                                                        
                                                       
                                                        
                                                        
                                                        
SOLUTION:
Given,
Area of plate,`A=0.6 m^2`
Velocity of the plate,`u=0.36`m/s
Thickness of the film,`dy=1.8`mm
Weight of the plate,` W=280 N`
Viscosity of the fluid,` mu=?`
 
 Now,
Shear force on the bottom surface of the plate is given by,
F= component of weight along the plane.
or, `F=W*sin30 =140 N`
Thus, shear stress `tau=F/A=140/0.6 =233.33` N/`m^2`
We have,
`tau=mu*(du)/(dy)`
or, `mu=233.33/0.36 *1.8/1000=1.166....Show More
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