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Quantity-of-Waste-Water

Determine quantity of sewage in `m^3`/sec for combined system from following data :
`50 %` of area is roofs and pavements (`C_1 = 0.8`)
`50 %` of area is vacant plots (`C_2 =0.1`)
Area of community ` 5` hectares
Population density = `700` persons/hectare
Water supply rate = `150` lpcd.
Peak factor = `3`
Time of concentration =`10` minutes.

Solution:

Average impermeability factor is,

`C=(C_1**A_1+C_2**A_2)/(A_1+A_2)`

`=(0.8**0.5+0.1**0.5)/1`

`=0.45`

Now, the sanitary discharge is given by,

`Q_(DWF)=(3**700*5**150**0.80)/(1000**86400)`

`=0.0146\ m^3/s`

Again,

The intensity of rainfall is,

`i=760/(10+10)=38` mm/hr

Now, the storm discharge is,

`Q_(WWF)=(CiA)/360`

`=(0.45**38**5)/360`

`=0.2375\ m^3/s`

Now, the quantity of sewage for the combined system is given by,

`Q=Q_(DWF)+Q_(WWF)`

`=0.0146+0.2375`

`=0.2521\ m^3/s`

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This chapter includes importance and objectives of waste management, sewage collection system, types of sewarage system, comparison of separate and combined system.

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Similar Question

This Chapter Quantity-of-Waste-Water consists of the following topics

The catchment area of the city is 500 hectares. Assuming that the surface on which rainfalls is classified as follows : :
S.NO Types of surface % area C
1 Forest and wooden area 10 0.15
2 open ground + unpaved street 10 0.20
3 parks + lawns + gardens 15 0.15
4 Gravel roads 20 0.25
5 Asphalt pavements 20 0.85
6 Water tight roof surfaces 25 0.9
Calculate the run off coefficient of the area. Also calculate the storm water, if the area to be served is 500 hectares, time of entry is 15 minutes and time of flow is 10 minutes.
[Ans: `0.5025`, `15.32 m^3/s`]

Determine quantity of sewage in `m^3`/sec for combined system from following data :
`50 %` of area is roofs and pavements (`C_1 = 0.8`)
`50 %` of area is vacant plots (`C_2 =0.1`)
Area of community ` 5` hectares
Population density = `700` persons/hectare
Water supply rate = `150` lpcd.
Peak factor = `3`
Time of concentration =`10` minutes.

An impervious area of `20` hectares is to be served by a sewer line. This area is subjected to three storms X, Y, Z with equal frequency of occurrence. The duration of the three storms is `20` minutes, `30` minutes and `35` minutes respectively. Taking the time of concentration equals to `30` minutes. Determine the maximum runoff from the each storm. [Ans : `0.938` `m^3`/s ,`1.134` `m^3`/s , `1.03` `m^3`/s]

Determine the quantity of sewage in `m^3`/sec for the combined system from the following data : `50 %` of the area is roofs and pavements (`C_1 = 0.8`) `50 %` of the area is vacant plots (`C_2 =0.1`) Area of the community ` 5` hectares Population density = `700` persons/hectare Water supply rate = `150` lpcd. Peak factor = `3` Time of concentration =`10` minutes.

Quantity of Waste Water

Sanitary-Engineering